Symmetrical polynomial under even permutation

\mathbf{Problem:} Let F be of characteristic \neq 2 and also let H be the subgroup of G=\text{Gal }E/F(p_1,p_2,\cdots,p_n) corresponding to the alternating group, that is the set of \zeta(\pi), \pi\in A_n. Show that \text{Inv}H=F(p_1,p_2,\cdots,p_n,\Delta) where \displaystyle\Delta=\prod\limits_{i<j}(x_i-x_j).

\mathbf{Proof:} It is a basic fact that \zeta(\pi)(\Delta)=\Delta when \pi is an even permutation and \zeta(\pi)(\Delta)=-\Delta when \pi is an odd permutation.

So all \pi\in H preserve \Delta and p_1,p_2,\cdots,p_n, which means F(p_1,p_2,\cdots,p_n,\Delta)\subset \text{Inv}H.

On the other hand no odd permutation can preserve \Delta, then \text{Gal }E/F(p_1,p_2,\cdots,p_n,\Delta)\leq H.

Combining these two, we know \text{Inv}H=F(p_1,p_2,\cdots,p_n,\Delta).

\text{Q.E.D}\hfill \square

\mathbf{Remark:} Jacobson p244.

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